(2c+)-3c=7(c+5)

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Solution for (2c+)-3c=7(c+5) equation: 



(2c+)-3c=7(c+5)

We move all terms to the left:

(2c+)-3c-(7(c+5))=0

We add all the numbers together, and all the variables

(+2c)-3c-(7(c+5))=0

We add all the numbers together, and all the variables

-3c+(+2c)-(7(c+5))=0

We get rid of parentheses

-3c+2c-(7(c+5))=0



We calculate terms in parentheses: -(7(c+5)), so:

7(c+5)

We multiply parentheses

7c+35

Back to the equation:

-(7c+35)



We add all the numbers together, and all the variables

-1c-(7c+35)=0

We get rid of parentheses

-1c-7c-35=0

We add all the numbers together, and all the variables

-8c-35=0

We move all terms containing c to the left, all other terms to the right

-8c=35

c=35/-8

c=-4+3/8

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