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3-23x=-14x(x-21)-15(x+33)
We move all terms to the left:
3-23x-(-14x(x-21)-15(x+33))=0
We calculate terms in parentheses: -(-14x(x-21)-15(x+33)), so:We get rid of parentheses
-14x(x-21)-15(x+33)
We multiply parentheses
-14x^2+294x-15x-495
We add all the numbers together, and all the variables
-14x^2+279x-495
Back to the equation:
-(-14x^2+279x-495)
14x^2-279x-23x+495+3=0
We add all the numbers together, and all the variables
14x^2-302x+498=0
a = 14; b = -302; c = +498;
Δ = b2-4ac
Δ = -3022-4·14·498
Δ = 63316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{63316}=\sqrt{4*15829}=\sqrt{4}*\sqrt{15829}=2\sqrt{15829}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-302)-2\sqrt{15829}}{2*14}=\frac{302-2\sqrt{15829}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-302)+2\sqrt{15829}}{2*14}=\frac{302+2\sqrt{15829}}{28} $
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