(2c)/11=(c-3)/4

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Solution for (2c)/11=(c-3)/4 equation: 



(2c)/11=(c-3)/4

We move all terms to the left:

(2c)/11-((c-3)/4)=0

We calculate fractions


8c^2/()+(-((c-3)*11)/()=0



We calculate terms in parentheses: +(-((c-3)*11)/(), so:

-((c-3)*11)/(

We multiply all the terms by the denominator


-((c-3)*11)



We calculate terms in parentheses: -((c-3)*11), so:

(c-3)*11

We multiply parentheses

11c-33

Back to the equation:

-(11c-33)



We get rid of parentheses

-11c+33

Back to the equation:

+(-11c+33)



We get rid of parentheses

8c^2/()-11c+33=0

We multiply all the terms by the denominator


8c^2-11c*()+33*()=0

We add all the numbers together, and all the variables

8c^2-11c*()=0

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