3(n+6)=4(n-2)

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Solution for 3(n+6)=4(n-2) equation: 



3(n+6)=4(n-2)

We move all terms to the left:

3(n+6)-(4(n-2))=0

We multiply parentheses

3n-(4(n-2))+18=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

3n-4n+8+18=0

We add all the numbers together, and all the variables

-1n+26=0

We move all terms containing n to the left, all other terms to the right

-n=-26

n=-26/-1

n=+26

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