(2b-4)/5=(b-2)/10

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Solution for (2b-4)/5=(b-2)/10 equation: 



(2b-4)/5=(b-2)/10

We move all terms to the left:

(2b-4)/5-((b-2)/10)=0

We calculate fractions


2b/()+(-((b-2)*5)/()=0



We calculate terms in parentheses: +(-((b-2)*5)/(), so:

-((b-2)*5)/(

We multiply all the terms by the denominator


-((b-2)*5)



We calculate terms in parentheses: -((b-2)*5), so:

(b-2)*5

We multiply parentheses

5b-10

Back to the equation:

-(5b-10)



We get rid of parentheses

-5b+10

Back to the equation:

+(-5b+10)



We get rid of parentheses

2b/()-5b+10=0

We multiply all the terms by the denominator


2b-5b*()+10*()=0

We add all the numbers together, and all the variables

2b-5b*()=0

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