(X-4)+10(3-x)=x-1

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Solution for (X-4)+10(3-x)=x-1 equation: 



(X-4)+10(3-X)=X-1

We move all terms to the left:

(X-4)+10(3-X)-(X-1)=0

We add all the numbers together, and all the variables

(X-4)+10(-1X+3)-(X-1)=0

We multiply parentheses

(X-4)-10X-(X-1)+30=0

We get rid of parentheses

X-10X-X-4+1+30=0

We add all the numbers together, and all the variables

-10X+27=0

We move all terms containing X to the left, all other terms to the right

-10X=-27

X=-27/-10

X=2+7/10

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