(2b+1)/b=3

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Solution for (2b+1)/b=3 equation: 



(2b+1)/b=3

We move all terms to the left:

(2b+1)/b-(3)=0



Domain of the equation: b!=0

b∈R



We multiply all the terms by the denominator


(2b+1)-3*b=0

We add all the numbers together, and all the variables

-3b+(2b+1)=0

We get rid of parentheses

-3b+2b+1=0

We add all the numbers together, and all the variables

-1b+1=0

We move all terms containing b to the left, all other terms to the right

-b=-1

b=-1/-1

b=1

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