1/3(y+1)+4=1/4(3y-2)-6

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Solution for 1/3(y+1)+4=1/4(3y-2)-6 equation: 



1/3(y+1)+4=1/4(3y-2)-6

We move all terms to the left:

1/3(y+1)+4-(1/4(3y-2)-6)=0



Domain of the equation: 3(y+1)!=0

y∈R





Domain of the equation: 4(3y-2)-6)!=0

y∈R



We calculate fractions


(4y3/(3(y+1)*4(3y-2))+(-3yy/(3(y+1)*4(3y-2))+4=0

We can not solve this equation

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