(2a/3)-(3a/6)=(1/6)

Solution for (2a/3)-(3a/6)=(1/6) equation:

(2a/3)-(3a/6)=(1/6)

We move all terms to the left:

(2a/3)-(3a/6)-((1/6))=0

We add all the numbers together, and all the variables

(+2a/3)-(+3a/6)-((+1/6))=0

We get rid of parentheses

2a/3-3a/6-((+1/6))=0

We calculate fractions


432a^2/()+(-9a)/()+()/()=0

We add all the numbers together, and all the variables

432a^2/()+(-9a)/()+1=0

We multiply all the terms by the denominator


432a^2+(-9a)+1*()=0

We add all the numbers together, and all the variables

432a^2+(-9a)=0

We get rid of parentheses

432a^2-9a=0

a = 432; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·432·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*432}=\frac{0}{864}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*432}=\frac{18}{864}
=1/48
$