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-(y+5)=2(3y+1)
We move all terms to the left:
-(y+5)-(2(3y+1))=0
We get rid of parentheses
-y-(2(3y+1))-5=0
We calculate terms in parentheses: -(2(3y+1)), so:We add all the numbers together, and all the variables
2(3y+1)
We multiply parentheses
6y+2
Back to the equation:
-(6y+2)
-1y-(6y+2)-5=0
We get rid of parentheses
-1y-6y-2-5=0
We add all the numbers together, and all the variables
-7y-7=0
We move all terms containing y to the left, all other terms to the right
-7y=7
y=7/-7
y=-1
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