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(2a-1)(2a-1)=25
We move all terms to the left:
(2a-1)(2a-1)-(25)=0
We multiply parentheses ..
(+4a^2-2a-2a+1)-25=0
We get rid of parentheses
4a^2-2a-2a+1-25=0
We add all the numbers together, and all the variables
4a^2-4a-24=0
a = 4; b = -4; c = -24;
Δ = b2-4ac
Δ = -42-4·4·(-24)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-20}{2*4}=\frac{-16}{8} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+20}{2*4}=\frac{24}{8} =3 $
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