5(m+3)-25=6(2+m)

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Solution for 5(m+3)-25=6(2+m) equation: 



5(m+3)-25=6(2+m)

We move all terms to the left:

5(m+3)-25-(6(2+m))=0

We add all the numbers together, and all the variables

5(m+3)-(6(m+2))-25=0

We multiply parentheses

5m-(6(m+2))+15-25=0



We calculate terms in parentheses: -(6(m+2)), so:

6(m+2)

We multiply parentheses

6m+12

Back to the equation:

-(6m+12)



We add all the numbers together, and all the variables

5m-(6m+12)-10=0

We get rid of parentheses

5m-6m-12-10=0

We add all the numbers together, and all the variables

-1m-22=0

We move all terms containing m to the left, all other terms to the right

-m=22

m=22/-1

m=-22

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