(2a+7)(3a+2)=0

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Solution for (2a+7)(3a+2)=0 equation:



(2a+7)(3a+2)=0
We multiply parentheses ..
(+6a^2+4a+21a+14)=0
We get rid of parentheses
6a^2+4a+21a+14=0
We add all the numbers together, and all the variables
6a^2+25a+14=0
a = 6; b = 25; c = +14;
Δ = b2-4ac
Δ = 252-4·6·14
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-17}{2*6}=\frac{-42}{12} =-3+1/2 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+17}{2*6}=\frac{-8}{12} =-2/3 $

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