X(3x+40)=17500

Solution for X(3x+40)=17500 equation:

X(3X+40)=17500

We move all terms to the left:

X(3X+40)-(17500)=0

We multiply parentheses

3X^2+40X-17500=0

a = 3; b = 40; c = -17500;
Δ = b2-4ac
Δ = 402-4·3·(-17500)
Δ = 211600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{211600}=460$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-460}{2*3}=\frac{-500}{6}
=-83+1/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+460}{2*3}=\frac{420}{6}
=70
$