(2a+2)(a+1)=

Solution for (2a+2)(a+1)= equation:

Simplifying
(2a + 2)(a + 1) = 0

Reorder the terms:
(2 + 2a)(a + 1) = 0

Reorder the terms:
(2 + 2a)(1 + a) = 0

Multiply (2 + 2a) * (1 + a)
(2(1 + a) + 2a * (1 + a)) = 0
((1 * 2 + a * 2) + 2a * (1 + a)) = 0
((2 + 2a) + 2a * (1 + a)) = 0
(2 + 2a + (1 * 2a + a * 2a)) = 0
(2 + 2a + (2a + 2a2)) = 0

Combine like terms: 2a + 2a = 4a
(2 + 4a + 2a2) = 0

Solving
2 + 4a + 2a2 = 0

Solving for variable 'a'.

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + 2a + a2) = 0

Factor a trinomial.
2((1 + a)(1 + a)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + a)' equal to zero and attempt to solve:

Simplifying
1 + a = 0

Solving
1 + a = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + a = 0 + -1

Combine like terms: 1 + -1 = 0
0 + a = 0 + -1
a = 0 + -1

Combine like terms: 0 + -1 = -1
a = -1

Simplifying
a = -1
Subproblem 2
Set the factor '(1 + a)' equal to zero and attempt to solve:

Simplifying
1 + a = 0

Solving
1 + a = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + a = 0 + -1

Combine like terms: 1 + -1 = 0
0 + a = 0 + -1
a = 0 + -1

Combine like terms: 0 + -1 = -1
a = -1

Simplifying
a = -1
Solution
a = {-1, -1}