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x in (-oo:+oo)
B = (5/6)*(A-12) // - (5/6)*(A-12)
B-((5/6)*(A-12)) = 0
(-5/6)*(A-12)+B = 0
B-5/6*(A-12) = 0
B-5/6*(A-12) = 0
B-5/6*A+10 = 0
B-5/6*A+10 = 0
x belongs to the empty set
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