(2X+33)=(x+48)

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Solution for (2X+33)=(x+48) equation: 



(2X+33)=(X+48)

We move all terms to the left:

(2X+33)-((X+48))=0

We get rid of parentheses

2X-((X+48))+33=0



We calculate terms in parentheses: -((X+48)), so:

(X+48)

We get rid of parentheses

X+48

Back to the equation:

-(X+48)



We get rid of parentheses

2X-X-48+33=0

We add all the numbers together, and all the variables

X-15=0

We move all terms containing X to the left, all other terms to the right

X=15

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