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(28+y)*y=288
We move all terms to the left:
(28+y)*y-(288)=0
We add all the numbers together, and all the variables
(y+28)*y-288=0
We multiply parentheses
y^2+28y-288=0
a = 1; b = 28; c = -288;
Δ = b2-4ac
Δ = 282-4·1·(-288)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-44}{2*1}=\frac{-72}{2} =-36 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+44}{2*1}=\frac{16}{2} =8 $
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