2-6m+9m*m-9=1118

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Solution for 2-6m+9m*m-9=1118 equation:



2-6m+9m*m-9=1118
We move all terms to the left:
2-6m+9m*m-9-(1118)=0
We add all the numbers together, and all the variables
-6m+9m*m-1125=0
Wy multiply elements
9m^2-6m-1125=0
a = 9; b = -6; c = -1125;
Δ = b2-4ac
Δ = -62-4·9·(-1125)
Δ = 40536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{40536}=\sqrt{36*1126}=\sqrt{36}*\sqrt{1126}=6\sqrt{1126}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{1126}}{2*9}=\frac{6-6\sqrt{1126}}{18} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{1126}}{2*9}=\frac{6+6\sqrt{1126}}{18} $

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