(27x-3)=((22x-19)-(2-11x))

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Solution for (27x-3)=((22x-19)-(2-11x)) equation: 



(27x-3)=((22x-19)-(2-11x))

We move all terms to the left:

(27x-3)-(((22x-19)-(2-11x)))=0

We add all the numbers together, and all the variables

(27x-3)-(((22x-19)-(-11x+2)))=0

We get rid of parentheses

27x-(((22x-19)-(-11x+2)))-3=0



We calculate terms in parentheses: -(((22x-19)-(-11x+2))), so:

((22x-19)-(-11x+2))



We calculate terms in parentheses: +((22x-19)-(-11x+2)), so:

(22x-19)-(-11x+2)

We get rid of parentheses

22x+11x-19-2

We add all the numbers together, and all the variables

33x-21

Back to the equation:

+(33x-21)



We get rid of parentheses

33x-21

Back to the equation:

-(33x-21)



We get rid of parentheses

27x-33x+21-3=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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