8x-(3x+(4-x))=4x+8

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Solution for 8x-(3x+(4-x))=4x+8 equation: 



8x-(3x+(4-x))=4x+8

We move all terms to the left:

8x-(3x+(4-x))-(4x+8)=0

We add all the numbers together, and all the variables

8x-(3x+(-1x+4))-(4x+8)=0

We get rid of parentheses

8x-(3x+(-1x+4))-4x-8=0



We calculate terms in parentheses: -(3x+(-1x+4)), so:

3x+(-1x+4)

We get rid of parentheses

3x-1x+4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

4x-(2x+4)-8=0

We get rid of parentheses

4x-2x-4-8=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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