(2500+.1(1.3x))+x+.3x=45435

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Solution for (2500+.1(1.3x))+x+.3x=45435 equation: 



(2500+.1(1.3x))+x+.3x=45435

We move all terms to the left:

(2500+.1(1.3x))+x+.3x-(45435)=0

We add all the numbers together, and all the variables

(2500+.1(+1.3x))+x+.3x-45435=0

We add all the numbers together, and all the variables

1.3x+(2500+.1(+1.3x))-45435=0



We calculate terms in parentheses: +(2500+.1(+1.3x)), so:

2500+.1(+1.3x)

determiningTheFunctionDomain
.1(+1.3x)+2500

We multiply parentheses

0.1x+2500

Back to the equation:

+(0.1x+2500)



We get rid of parentheses

1.3x+0.1x+2500-45435=0

We add all the numbers together, and all the variables

1.4x-42935=0

We move all terms containing x to the left, all other terms to the right

1.4x=42935

x=42935/1.4

x=30667+1/1.1666666666624

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