5(3a+2)+5(5+4a)=5(a+2)

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Solution for 5(3a+2)+5(5+4a)=5(a+2) equation: 



5(3a+2)+5(5+4a)=5(a+2)

We move all terms to the left:

5(3a+2)+5(5+4a)-(5(a+2))=0

We add all the numbers together, and all the variables

5(3a+2)+5(4a+5)-(5(a+2))=0

We multiply parentheses

15a+20a-(5(a+2))+10+25=0



We calculate terms in parentheses: -(5(a+2)), so:

5(a+2)

We multiply parentheses

5a+10

Back to the equation:

-(5a+10)



We add all the numbers together, and all the variables

35a-(5a+10)+35=0

We get rid of parentheses

35a-5a-10+35=0

We add all the numbers together, and all the variables

30a+25=0

We move all terms containing a to the left, all other terms to the right

30a=-25

a=-25/30

a=-5/6

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