(235/sin(53))=x/sin(18)

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Solution for (235/sin(53))=x/sin(18) equation: 


D( x )

sin(18) = 0

sin(53) = 0

sin(18) = 0

sin(18) = 0

t_1 = sin(18)

sin(18) = 0

t_1 = 0

x należy do R

x in (-oo:+oo)

sin(53) = 0

sin(53) = 0

t_2 = sin(53)

sin(53) = 0

t_2 = 0

x należy do R

x in (-oo:+oo)

x belongs to the empty set

235/sin(53) = x/sin(18)

x belongs to the empty set

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