1/y=y/36

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Solution for 1/y=y/36 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y = y/36 // - y/36

1/y-(y/36) = 0

1*y^-1-1/36*y^1 = 0

(1*y^0-1/36*y^2)/(y^1) = 0 // * y^2

y^1*(1*y^0-1/36*y^2) = 0

y^1

(-1/36)*y^2+1 = 0

(-1/36)*y^2+1 = 0

DELTA = 0^2-(1*4*(-1/36))

DELTA = 1/9

DELTA > 0

y = ((1/9)^(1/2)+0)/(2*(-1/36)) or y = (0-(1/9)^(1/2))/(2*(-1/36))

y = -6 or y = 6

y in { -6, 6} 

y in { -6, 6 }

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