(23+3x)=(76-9x)

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Solution for (23+3x)=(76-9x) equation: 



(23+3x)=(76-9x)

We move all terms to the left:

(23+3x)-((76-9x))=0

We add all the numbers together, and all the variables

(3x+23)-((-9x+76))=0

We get rid of parentheses

3x-((-9x+76))+23=0



We calculate terms in parentheses: -((-9x+76)), so:

(-9x+76)

We get rid of parentheses

-9x+76

Back to the equation:

-(-9x+76)



We get rid of parentheses

3x+9x-76+23=0

We add all the numbers together, and all the variables

12x-53=0

We move all terms containing x to the left, all other terms to the right

12x=53

x=53/12

x=4+5/12

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