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(22+2x)(18+2x)=1152
We move all terms to the left:
(22+2x)(18+2x)-(1152)=0
We add all the numbers together, and all the variables
(2x+22)(2x+18)-1152=0
We multiply parentheses ..
(+4x^2+36x+44x+396)-1152=0
We get rid of parentheses
4x^2+36x+44x+396-1152=0
We add all the numbers together, and all the variables
4x^2+80x-756=0
a = 4; b = 80; c = -756;
Δ = b2-4ac
Δ = 802-4·4·(-756)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18496}=136$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-136}{2*4}=\frac{-216}{8} =-27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+136}{2*4}=\frac{56}{8} =7 $
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