(20y+12)=(16y+20)

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Solution for (20y+12)=(16y+20) equation: 



(20y+12)=(16y+20)

We move all terms to the left:

(20y+12)-((16y+20))=0

We get rid of parentheses

20y-((16y+20))+12=0



We calculate terms in parentheses: -((16y+20)), so:

(16y+20)

We get rid of parentheses

16y+20

Back to the equation:

-(16y+20)



We get rid of parentheses

20y-16y-20+12=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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