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x+1=(2)/(3)(x+3)
We move all terms to the left:
x+1-((2)/(3)(x+3))=0
Domain of the equation: 3(x+3))!=0We multiply all the terms by the denominator
x∈R
x*3(x+3))-(2+1*3(x+3))=0
Wy multiply elements
3x^2(x+3x(x=0
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