(20-2x)/3=(4x+7)/4

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Solution for (20-2x)/3=(4x+7)/4 equation: 



(20-2x)/3=(4x+7)/4

We move all terms to the left:

(20-2x)/3-((4x+7)/4)=0

We add all the numbers together, and all the variables

(-2x+20)/3-((4x+7)/4)=0

We calculate fractions


(-2x)/()+(-((4x+7)*3)/()=0



We calculate terms in parentheses: +(-((4x+7)*3)/(), so:

-((4x+7)*3)/(

We multiply all the terms by the denominator


-((4x+7)*3)



We calculate terms in parentheses: -((4x+7)*3), so:

(4x+7)*3

We multiply parentheses

12x+21

Back to the equation:

-(12x+21)



We get rid of parentheses

-12x-21

Back to the equation:

+(-12x-21)



We get rid of parentheses

(-2x)/()-12x-21=0

We multiply all the terms by the denominator


(-2x)-12x*()-21*()=0

We add all the numbers together, and all the variables

(-2x)-12x*()=0

We get rid of parentheses

-2x-12x*()=0

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