7(x+1)+3(x+2)=42

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Solution for 7(x+1)+3(x+2)=42 equation: 



7(x+1)+3(x+2)=42

We move all terms to the left:

7(x+1)+3(x+2)-(42)=0

We multiply parentheses

7x+3x+7+6-42=0

We add all the numbers together, and all the variables

10x-29=0

We move all terms containing x to the left, all other terms to the right

10x=29

x=29/10

x=2+9/10

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