(20+3x)(70-8x)=1426

Solution for (20+3x)(70-8x)=1426 equation:

(20+3x)(70-8x)=1426

We move all terms to the left:

(20+3x)(70-8x)-(1426)=0

We add all the numbers together, and all the variables

(3x+20)(-8x+70)-1426=0

We multiply parentheses ..

(-24x^2+210x-160x+1400)-1426=0

We get rid of parentheses

-24x^2+210x-160x+1400-1426=0

We add all the numbers together, and all the variables

-24x^2+50x-26=0

a = -24; b = 50; c = -26;
Δ = b2-4ac
Δ = 502-4·(-24)·(-26)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2}{2*-24}=\frac{-52}{-48}
=1+1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2}{2*-24}=\frac{-48}{-48}
=1
$