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(20+2x)(28+2x)=2100
We move all terms to the left:
(20+2x)(28+2x)-(2100)=0
We add all the numbers together, and all the variables
(2x+20)(2x+28)-2100=0
We multiply parentheses ..
(+4x^2+56x+40x+560)-2100=0
We get rid of parentheses
4x^2+56x+40x+560-2100=0
We add all the numbers together, and all the variables
4x^2+96x-1540=0
a = 4; b = 96; c = -1540;
Δ = b2-4ac
Δ = 962-4·4·(-1540)
Δ = 33856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{33856}=184$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-184}{2*4}=\frac{-280}{8} =-35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+184}{2*4}=\frac{88}{8} =11 $
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