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(2/y)+(4/y-4)=(2/3)
We move all terms to the left:
(2/y)+(4/y-4)-((2/3))=0
Domain of the equation: y)!=0
y!=0/1
y!=0
y∈R
Domain of the equation: y-4)!=0We add all the numbers together, and all the variables
y∈R
(+2/y)+(4/y-4)-((+2/3))=0
We get rid of parentheses
2/y+4/y-4-((+2/3))=0
We calculate fractions
()/3y^2+(-((+2*y)/3y^2-4=0
We add all the numbers together, and all the variables
()/3y^2+(-((+2y)/3y^2-4=0
We calculate fractions
We do not support eypression: y^4
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