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-8x^2+3x=-100
We move all terms to the left:
-8x^2+3x-(-100)=0
We add all the numbers together, and all the variables
-8x^2+3x+100=0
a = -8; b = 3; c = +100;
Δ = b2-4ac
Δ = 32-4·(-8)·100
Δ = 3209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3209}}{2*-8}=\frac{-3-\sqrt{3209}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3209}}{2*-8}=\frac{-3+\sqrt{3209}}{-16} $
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