(2/9)x+(1/2)x=39

Solution for (2/9)x+(1/2)x=39 equation:

(2/9)x+(1/2)x=39

We move all terms to the left:

(2/9)x+(1/2)x-(39)=0


Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/9)x+(+1/2)x-39=0

We multiply parentheses

2x^2+x^2-39=0

We add all the numbers together, and all the variables

3x^2-39=0

a = 3; b = 0; c = -39;
Δ = b2-4ac
Δ = 02-4·3·(-39)
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{13}}{2*3}=\frac{0-6\sqrt{13}}{6}
=-\frac{6\sqrt{13}}{6}
=-\sqrt{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{13}}{2*3}=\frac{0+6\sqrt{13}}{6}
=\frac{6\sqrt{13}}{6}
=\sqrt{13}
$