t2-2.1t+0.8=0

Solution for t2-2.1t+0.8=0 equation:

t2-2.1t+0.8=0

We add all the numbers together, and all the variables

t^2-2.1t+0.8=0

a = 1; b = -2.1; c = +0.8;
Δ = b2-4ac
Δ = -2.12-4·1·0.8
Δ = 1.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.1)-\sqrt{1.21}}{2*1}=\frac{2.1-\sqrt{1.21}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.1)+\sqrt{1.21}}{2*1}=\frac{2.1+\sqrt{1.21}}{2}
$