(2/7)+(7m/4)=(71/28)

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Solution for (2/7)+(7m/4)=(71/28) equation: 



(2/7)+(7m/4)=(71/28)

We move all terms to the left:

(2/7)+(7m/4)-((71/28))=0

We add all the numbers together, and all the variables

(+7m/4)+(+2/7)-((+71/28))=0

We get rid of parentheses

7m/4+2/7-((+71/28))=0

We calculate fractions


2744m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

2744m^2/()+2=0

We multiply all the terms by the denominator


2744m^2+2*()=0

We add all the numbers together, and all the variables

2744m^2=0

a = 2744; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2744·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{5488}=0$

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