4(1j-3)=9(1j+2)

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Solution for 4(1j-3)=9(1j+2) equation: 



4(1j-3)=9(1j+2)

We move all terms to the left:

4(1j-3)-(9(1j+2))=0

We add all the numbers together, and all the variables

4(j-3)-(9(j+2))=0

We multiply parentheses

4j-(9(j+2))-12=0



We calculate terms in parentheses: -(9(j+2)), so:

9(j+2)

We multiply parentheses

9j+18

Back to the equation:

-(9j+18)



We get rid of parentheses

4j-9j-18-12=0

We add all the numbers together, and all the variables

-5j-30=0

We move all terms containing j to the left, all other terms to the right

-5j=30

j=30/-5

j=-6

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