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(2/5f+12)-(3/10f-9=)
We move all terms to the left:
(2/5f+12)-(3/10f-9-())=0
Domain of the equation: 5f+12)!=0
f∈R
Domain of the equation: 10f-9-())!=0We get rid of parentheses
We move all terms containing f to the left, all other terms to the right
10f-())!=9
f∈R
2/5f-(3/10f-9-())+12=0
We calculate fractions
20f/50f^2+(-(3*5f)/50f^2+12=0
We add all the numbers together, and all the variables
20f/50f^2+(-(+3*5f)/50f^2+12=0
We calculate fractions
We do not support efpression: f^4
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