3(3z+4)=6(5z+2)

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Solution for 3(3z+4)=6(5z+2) equation: 



3(3z+4)=6(5z+2)

We move all terms to the left:

3(3z+4)-(6(5z+2))=0

We multiply parentheses

9z-(6(5z+2))+12=0



We calculate terms in parentheses: -(6(5z+2)), so:

6(5z+2)

We multiply parentheses

30z+12

Back to the equation:

-(30z+12)



We get rid of parentheses

9z-30z-12+12=0

We add all the numbers together, and all the variables

-21z=0

z=0/-21

z=0

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