(2/5)y+6=(1/3)y

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Solution for (2/5)y+6=(1/3)y equation:



(2/5)y+6=(1/3)y
We move all terms to the left:
(2/5)y+6-((1/3)y)=0
Domain of the equation: 5)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 3)y)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+2/5)y-((+1/3)y)+6=0
We multiply parentheses
2y^2-((+1/3)y)+6=0
We multiply all the terms by the denominator
2y^2*3)y)-((+6*3)y)+1=0
We add all the numbers together, and all the variables
2y^2*3)y)-(18y)+1=0
We add all the numbers together, and all the variables
2y^2*3)y)-18y+1=0
Wy multiply elements
6y^3=0
We do not support eypression: y^3

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