4(d-2)=2(d+3)=

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Solution for 4(d-2)=2(d+3)= equation: 



4(d-2)=2(d+3)=

We move all terms to the left:

4(d-2)-(2(d+3))=0

We multiply parentheses

4d-(2(d+3))-8=0



We calculate terms in parentheses: -(2(d+3)), so:

2(d+3)

We multiply parentheses

2d+6

Back to the equation:

-(2d+6)



We get rid of parentheses

4d-2d-6-8=0

We add all the numbers together, and all the variables

2d-14=0

We move all terms containing d to the left, all other terms to the right

2d=14

d=14/2

d=7

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