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(2/5)x(10x+5)=18
We move all terms to the left:
(2/5)x(10x+5)-(18)=0
Domain of the equation: 5)x(10x+5)!=0We add all the numbers together, and all the variables
x∈R
(+2/5)x(10x+5)-18=0
We multiply all the terms by the denominator
(+2-18*5)x(10x+5)=0
We add all the numbers together, and all the variables
(-88)x(10x+5)=0
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