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3(4x+1)=2(3x-4)
We move all terms to the left:
3(4x+1)-(2(3x-4))=0
We multiply parentheses
12x-(2(3x-4))+3=0
We calculate terms in parentheses: -(2(3x-4)), so:We get rid of parentheses
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
12x-6x+8+3=0
We add all the numbers together, and all the variables
6x+11=0
We move all terms containing x to the left, all other terms to the right
6x=-11
x=-11/6
x=-1+5/6
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