(2/5)k+3=-5

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Solution for (2/5)k+3=-5 equation: 



(2/5)k+3=-5

We move all terms to the left:

(2/5)k+3-(-5)=0



Domain of the equation: 5)k!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+2/5)k+3-(-5)=0

We add all the numbers together, and all the variables

(+2/5)k+8=0

We multiply parentheses

2k^2+8=0

a = 2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·2·8
Δ = -64
Delta is less than zero, so there is no solution for the equation

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