12x+(-8)=40x+3

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Solution for 12x+(-8)=40x+3 equation: 



12x+(-8)=40x+3

We move all terms to the left:

12x+(-8)-(40x+3)=0

We add all the numbers together, and all the variables

12x-(40x+3)-8=0

We get rid of parentheses

12x-40x-3-8=0

We add all the numbers together, and all the variables

-28x-11=0

We move all terms containing x to the left, all other terms to the right

-28x=11

x=11/-28

x=-11/28

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