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(2/3x)+(1/6)=(3/2x)
We move all terms to the left:
(2/3x)+(1/6)-((3/2x))=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)-((+3/2x))+(+1/6)=0
We get rid of parentheses
2/3x-((+3/2x))+1/6=0
We calculate fractions
(-((+3*3x*6)/36x^2+12x^2/36x^2+24x/36x^2=0
We can not solve this equation
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