2x+3(2x-11)=x+67

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Solution for 2x+3(2x-11)=x+67 equation: 



2x+3(2x-11)=x+67

We move all terms to the left:

2x+3(2x-11)-(x+67)=0

We multiply parentheses

2x+6x-(x+67)-33=0

We get rid of parentheses

2x+6x-x-67-33=0

We add all the numbers together, and all the variables

7x-100=0

We move all terms containing x to the left, all other terms to the right

7x=100

x=100/7

x=14+2/7

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