(2/3)y=2y/3

Solution for (2/3)y=2y/3 equation:

(2/3)y=2y/3

We move all terms to the left:

(2/3)y-(2y/3)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+2/3)y-(+2y/3)=0

We multiply parentheses

2y^2-(+2y/3)=0

We get rid of parentheses

2y^2-2y/3=0

We multiply all the terms by the denominator


2y^2*3-2y=0

Wy multiply elements

6y^2-2y=0

a = 6; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·6·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*6}=\frac{0}{12}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*6}=\frac{4}{12}
=1/3
$